39x^2+2)=18

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Solution for 39x^2+2)=18 equation: 



39x^2+2)=18

We move all terms to the left:

39x^2+2)-(18)=0

We add all the numbers together, and all the variables

39x^2=0

a = 39; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·39·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{78}=0$

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